用俩案例推一遍就行了,一定是离哪边远长的时间越长
#include<iostream>
using namespace std;
const int N = 1e4 + 10;
int n;
int main()
{
cin>>n;
for(int i = 1;i <= n;i ++)
{
int x1 = n - i;
int x2 = i - 1;
// cout<<"X1 "<<x1<<" x2 "<<x2<<endl;
int bigger = max(x2,x1);
cout<<bigger * 2<<endl;
}
}