能闪则闪,分批进行
#include <iostream>
using namespace std;
int m, s, t;
int need_time, x;
int main()
{
cin >> m >> s >> t;
int s1 = 0, s2 = 0;
for(int i = 1; i <= t; i++)
{
s1 += 17;
if(m >= 10)
{
s2 += 60;
m -= 10;
}
else
m += 4;
if(s1 < s2)
s1 = s2;
if(s1 >= s)
{
cout << "Yes" << endl << i;
break;
}
}
if(s1 < s)
cout << "No" << endl << s1;
return 0;
}