#include<iostream>
using namespace std;
double A(int x){//求x的阶乘
if(x==1) return 1;
return A(x-1)*x;
}
int situation(int n,int m){//套计算公式---s=(n+m)!/(n!*m!)
int s=A(n+m)/(A(n)*A(m));
return s;
}
int main(){
int n,m;
cin>>n>>m;
cout<<situation(n,m);
return 0;
}