两个map解决
#include<iostream>
#include<vector>
#include<set>
#include<map>
using namespace std;
//记录每个字母要按多少次
map<char,int> inputMap = {
{'a',1},{'b',2},{'c',3},
{'d',1},{'e',2},{'f',3},
{'g',1},{'h',2},{'i',3},
{'j',1},{'k',2},{'l',3},
{'m',1},{'n',2},{'o',3},
{'p',1},{'q',2},{'r',3},{'s',4},
{'t',1},{'u',2},{'v',3},
{'w',1},{'x',2},{'y',3},{'z',4}
};
//用map记录每个字母在哪个按键上
map<char,int> keyMap = {
{'a',2},{'b',2},{'c',2},
{'d',3},{'e',3},{'f',3},
{'g',4},{'h',4},{'i',4},
{'j',5},{'k',5},{'l',5},
{'m',6},{'n',6},{'o',6},
{'p',7},{'q',7},{'r',7},{'s',7},
{'t',8},{'u',8},{'v',8},
{'w',9},{'x',9},{'y',9},{'z',9}
};
int main(){
string s;
while(getline(cin,s)){
int lastKey = -1;//上一次按下的按键
int res = 0;
for(int i = 0;i < s.size();i++){
if(keyMap[s[i]] == lastKey){//连续两字符在同一个按键上,等一段时间再按
res += 2;//花费两个时间段
}
res += inputMap[s[i]];
lastKey = keyMap[s[i]];
}
cout<<res<<endl;
}
return 0;
}