AcWing 671. DDD
原题链接
简单
作者:
落花无意
,
2023-10-10 15:00:25
,
所有人可见
,
阅读 70
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
int DDD;
cin>>DDD;
if(DDD==61) cout<<"Brasilia"<<endl;
else if(DDD==71) cout<<"Salvador"<<endl;
else if(DDD==11) cout<<"Sao Paulo"<<endl;
else if(DDD==21) cout<<"Rio de Janeiro"<<endl;
else if(DDD==32) cout<<"Juiz de Fora"<<endl;
else if(DDD==19) cout<<"Campinas"<<endl;
else if(DDD==27) cout<<"Vitoria"<<endl;
else if(DDD==31) cout<<"Belo Horizonte"<<endl;
else cout<<"DDD nao cadastrado"<<endl;
return 0;
}