//简单模拟
#include<iostream>
#include<cmath>
using namespace std;
const int N=1010;
double w[N];
int main()
{
int n;
cin>>n;
int sum=0;
for(int i=1;i<=n;++i)
{
cin>>w[i];
sum+=w[i];
}
double averge=(double)sum/n;
double sumvariance=0;
for(int i=1;i<=n;++i)
{
sumvariance+=(w[i]-averge)*(w[i]-averge);
}
double variance=sumvariance/n;
for(int i=1;i<=n;++i)
{
cout<<(w[i]-averge)/sqrt(variance)<<endl;
}
return 0;
}