C++ 代码
#include <iostream>
#include <cstdio>
#include <cmath>
#define N 1005
using namespace std;
int n;
long double ave, sq, a[N];
int main ()
{
cin >> n;
for (int i = 1; i <= n; i ++)
{
cin >> a[i], ave += a[i];
}
ave /= n;
for (int i = 1; i <= n; i ++)
{
sq += (a[i] - ave) * (a[i] - ave);
}
sq /= n;
for (int i = 1; i <= n; i ++)
{
printf ("%LF\n", (a[i] - ave) / sqrt (sq));
}
return 0;
}