C# 数学代码
public class Solution {
public int MissingNumber(int[] nums) {
int n = nums.Length;
int result = n * (1 + n) / 2;
foreach (int num in nums){
result -= num;
}
return result;
}
}
C# 排序代码
public class Solution {
public int MissingNumber(int[] nums) {
Array.Sort(nums);
for (int i = 0; i < nums.Length; i++){
if (nums[i] != i) return i;
}
return nums.Length;
}
}