//658 一元二次方程公式
include[HTML_REMOVED]
include[HTML_REMOVED]
int main()
{
double a,b,c,R1,R2;
scanf(“%lf%lf%lf”,&a,&b,&c);
if(bb-4ac<0||a==0)
printf(“Impossivel calcular”);
else
{
R1=(-b+sqrt(bb-4ac))/2/a;
R2=(-b-sqrt(bb-4a*c))/2/a;
printf(“R1 = %.5lf\nR2 = %.5lf”,R1,R2);
}
return 0;
}