658一元二次方程公式
include[HTML_REMOVED]
include[HTML_REMOVED]
using namespace std;
int main()
{
double a,b,c;
scanf(“%lf%lf%lf”,&a,&b,&c);
if(bb-4ac<0||a==0)
printf(“Impossivel calcular”);
else
printf(“R1 = %.5lf\nR2 = %.5lf\n”,(-b+sqrt(bb-4ac))/(2a),(-b-sqrt(bb-4ac))/(2*a));
return 0;
}