Java
import java.util.Scanner;
public class Main{
static int N = 100003,idx;
static int[] e = new int[N];
static int[] ne = new int[N];
static int[] h = new int[N];
static void add(int x){
int k = (x % N + N) % N;
e[idx] = x;
ne[idx] = h[k];
h[k] = idx++;
}
static void find(int x){
int k = (x % N + N) % N;
for(int i = h[k]; i != -1; i = ne[i]){
if(e[i] == x){
System.out.println("Yes");
return;
}
}
System.out.println("No");
}
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
idx = 0;
for(int i = 0; i < N; i++)h[i] = -1;
while(n -- > 0){
String s = scan.next();
int a = scan.nextInt();
if(s.equals("I")){
add(a);
}else{
find(a);
}
}
}
}
C++
拉链法
#include <iostream>
#include <cstring>
using namespace std;
const int N = 100003;
int h[N], e[N], ne[N], idx;
void insert(int x)
{
int k = (x % N + N) % N;
e[idx] = x, ne[idx] = h[k], h[k] = idx ++;
}
bool find(int x)
{
int k = (x % N + N) % N;
for(int i = h[k]; i != -1; i = ne[i])
if(e[i] == x)
return true;
return false;
}
int main()
{
int n;
memset(h, -1, sizeof h);
scanf("%d", &n);
while(n --)
{
char op[2];
int x;
scanf("%s%d", op, &x);
if(op[0] == 'I') insert(x);
else
{
if(find(x)) puts("Yes");
else puts("No");
}
}
return 0;
}
开放寻址法
#include <iostream>
#include <cstring>
using namespace std;
const int N = 200003, null = 0x3f3f3f3f;
int h[N];
int find(int x)
{
int k = (x % N + N) % N;
while(h[k] != null && h[k] != x)
{
k ++;
if(k == N) k = 0;
}
return k;
}
int main()
{
int n;
scanf("%d", &n);
memset(h, 0x3f, sizeof h);
while(n --)
{
char op[2];
int x;
scanf("%s%d", op, &x);
int k = find(x);
if(op[0] == 'I') h[k] = x;
else
{
if(h[k] != null) puts("Yes");
else puts("No");
}
}
return 0;
}