不用long long，用log(a*b) = log(a+b)这个性质来做，但是需要定义一个误差来避免精度丢失。

#include<iostream>
#include<cmath>
using namespace std;
const double eps=1e-5;
int main(){
    int a,b,c;
    while(cin >> a >> b >> c){
        if(a+b==c || abs(a-b)==c || abs(log(a)+log(b)-log(c)) <eps || abs(abs(log(a)-log(b))-log(c))<eps) cout << "YES" <<endl;
        else cout<<"NO"<<endl;
    }
    return 0;
}