Flood Fill 问题
算法小菜第一次写题解,就是简单贴一下打卡代码,尝试一下,后面一定详细写
BFS
#include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <queue>
#define x first
#define y second
using namespace std;
const int N = 1010, M = N * N;
typedef pair<int, int> PII;
int n, m;
PII q[M]; //模拟队列数组
char g[N][N];
bool st[N][N];
/*模拟队列
void bfs(int sx, int sy)
{
int hh = 0, tt = 0;
q[0] = {sx, sy};
st[sx][sy] = true;
while (hh <= tt)
{
PII t = q[hh ++ ];
for (int i = t.x - 1; i <= t.x + 1; i ++ )
for (int j = t.y - 1; j <= t.y + 1; j ++ )
{
if (i == t.x && j == t.y) continue;
if (i < 0 || i >= n || j < 0 || j >= m) continue;
if (g[i][j] == '.' || st[i][j]) continue;
q[ ++ tt] = {i, j};
st[i][j] = true;
}
}
}*/
void bfs(int sx, int sy)
{
queue<PII> q;
q.push({sx, sy});
st[sx][sy] = true;
while (q.size())
{
PII t = q.front();
q.pop();
for (int i = t.x - 1; i <= t.x + 1; i ++ )
for (int j = t.y - 1; j <= t.y + 1; j ++ )
{
if (i == t.x && j == t.y) continue;
if (i < 0 || i >= n || j < 0 || j >= m) continue;
if (g[i][j] == '.' || st[i][j]) continue;
q.push({i, j});
st[i][j] = true;
}
}
}
int main()
{
scanf("%d%d", &n, &m);
for (int i = 0; i < n; i ++ ) scanf("%s", g[i]);
int cnt = 0;
for (int i = 0; i < n; i ++ )
for (int j = 0; j < m; j ++ )
{
if (!st[i][j] && g[i][j] == 'W')
{
bfs(i, j);
cnt ++;
}
}
cout << cnt << endl;
return 0;
}
DFS 借鉴大佬思路
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std;
const int N = 1010;
int dx[] = {1, 1, 1, 0, 0, -1, -1, -1};
int dy[] = {-1, 0, 1, -1, 1, -1, 0, 1};
int n, m, cnt;
char g[N][N];
void dfs(int x, int y)
{
for (int i = 0; i < 8; i ++ )
{
int tx = x + dx[i], ty = y + dy[i];
if (tx < 0 || tx >= n || ty < 0 || ty >= m || g[tx][ty] == '.') continue;
g[tx][ty] = '.'; //标记搜过并以该点为起始点
dfs(tx, ty);
}
}
int main()
{
cin >> n >> m;
for (int i = 0; i < n; i ++ ) scanf("%s", &g[i]);
for (int i = 0; i < n; i ++ )
for (int j = 0; j < m; j ++ )
{
if (g[i][j] == 'W')
{
dfs(i, j);
cnt ++;
}
}
cout << cnt << endl;
return 0;
}