作者:
MyPower
,
2023-05-03 15:00:29
,
所有人可见
,
阅读 7
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 210, INF = 1e9;
int n, m, q;
int d[N][N];
void floyd()
{
for(int k = 1; k <= n; k ++)
for(int i = 1; i <= n; i ++)
for(int j = 1; j <= n; j ++)
d[i][j] = min(d[i][j], d[i][k] + d[k][j]);
}
int main()
{
scanf("%d%d%d", &n, &m, &q);
for(int i = 1; i <= n; i ++)
for(int j = 1; j <= n; j++)
if(i == j) d[i][j] = 0;
else d[i][j] = INF;
while(m -- )
{
int a, b, w;
scanf("%d%d%d", &a, &b, &w);
d[a][b] = min(d[a][b], w);
}
floyd();
while(q --)
{
int a, b;
scanf("%d%d", &a, &b);
if(d[a][b] > INF / 2) cout << "impossible" << endl;
else printf("%d\n", d[a][b]);
}
return 0;
}