作者:
fangy
,
2023-03-17 15:12:53
,
所有人可见
,
阅读 7
开放寻址法
#include <iostream>
#include <cstring>
using namespace std;
const int N = 200003, null = 0x3f3f3f3f;
int h[N];
int find(int x)
{
int k = (x % N + N) % N;
while (h[k] != null && h[k] != x)
{
k++;
if (k == N) k = 0;
}
return k;
}
int main()
{
int T;
cin >> T;
memset(h, 0x3f, sizeof h);
while (T--)
{
char op[2];
int x;
scanf("%s%d", op, &x);
int k = find(x);
if (op[0] == 'I') h[k] = x;
else puts(h[k] == x ? "Yes" : "No");
}
return 0;
}
拉链法
#include <iostream>
#include <cstring>
using namespace std;
const int N = 100003;
int h[N], e[N], ne[N], idx;
void insert(int x)
{
int k = (x % N + N) % N;
e[idx] = x, ne[idx] = h[k], h[k] = idx++;
}
bool find(int x)
{
int k = (x % N + N) % N;
for (int i = h[k]; i != -1; i = ne[i])
if (e[i] == x)
return true;
return false;
}
int main()
{
int T;
cin >> T;
memset(h, -1, sizeof h);
while (T--)
{
char op[2];
int x;
scanf("%s%d", op, &x);
if (op[0] == 'I') insert(x);
else puts(find(x)? "Yes" : "No");
}
return 0;
}